-2x^2+4=6x^2-5x

Solution for -2x^2+4=6x^2-5x equation:

-2x^2+4=6x^2-5x

We move all terms to the left:

-2x^2+4-(6x^2-5x)=0

We get rid of parentheses

-2x^2-6x^2+5x+4=0

We add all the numbers together, and all the variables

-8x^2+5x+4=0

a = -8; b = 5; c = +4;
Δ = b2-4ac
Δ = 52-4·(-8)·4
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{17}}{2*-8}=\frac{-5-3\sqrt{17}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{17}}{2*-8}=\frac{-5+3\sqrt{17}}{-16}
$